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v^2+17v+10=0
a = 1; b = 17; c = +10;
Δ = b2-4ac
Δ = 172-4·1·10
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{249}}{2*1}=\frac{-17-\sqrt{249}}{2} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{249}}{2*1}=\frac{-17+\sqrt{249}}{2} $
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